mirror of
https://github.com/josdejong/mathjs.git
synced 2025-12-08 19:46:04 +00:00
135 lines
3.3 KiB
JavaScript
135 lines
3.3 KiB
JavaScript
'use strict';
|
|
|
|
function factory (type, config, load, typed) {
|
|
var collection = load(require('../../type/collection'));
|
|
|
|
/**
|
|
* Calculate the nth root of a value.
|
|
* The principal nth root of a positive real number A, is the positive real
|
|
* solution of the equation
|
|
*
|
|
* x^root = A
|
|
*
|
|
* For matrices, the function is evaluated element wise.
|
|
*
|
|
* Syntax:
|
|
*
|
|
* math.nthRoot(a)
|
|
* math.nthRoot(a, root)
|
|
*
|
|
* Examples:
|
|
*
|
|
* math.nthRoot(9, 2); // returns 3, as 3^2 == 9
|
|
* math.sqrt(9); // returns 3, as 3^2 == 9
|
|
* math.nthRoot(64, 3); // returns 4, as 4^3 == 64
|
|
*
|
|
* See also:
|
|
*
|
|
* sqrt, pow
|
|
*
|
|
* @param {Number | BigNumber | Boolean | Array | Matrix | null} a
|
|
* Value for which to calculate the nth root
|
|
* @param {Number | BigNumber | Boolean | null} [root=2] The root.
|
|
* @return {Number | Complex | Array | Matrix} Returns the nth root of `a`
|
|
*/
|
|
var nthRoot = typed('nthRoot', {
|
|
'number': function (x) {
|
|
return _nthRoot(x, 2);
|
|
},
|
|
'number, number': _nthRoot,
|
|
|
|
'BigNumber': function (x) {
|
|
return _bigNthRoot(x, new type.BigNumber(2));
|
|
},
|
|
'BigNumber, BigNumber': _bigNthRoot,
|
|
|
|
'Array | Matrix': function (x) {
|
|
return collection.deepMap(x, nthRoot);
|
|
},
|
|
|
|
'Array | Matrix, any': function (x, root) {
|
|
return collection.deepMap2(x, root, nthRoot);
|
|
},
|
|
|
|
'any, Array | Matrix': function (x, root) {
|
|
return collection.deepMap2(x, root, nthRoot);
|
|
}
|
|
});
|
|
|
|
return nthRoot;
|
|
|
|
/**
|
|
* Calculate the nth root of a for BigNumbers, solve x^root == a
|
|
* http://rosettacode.org/wiki/Nth_root#JavaScript
|
|
* @param {BigNumber} a
|
|
* @param {BigNumber} root
|
|
* @private
|
|
*/
|
|
function _bigNthRoot(a, root) {
|
|
var zero = new type.BigNumber(0);
|
|
var one = new type.BigNumber(1);
|
|
var inv = root.isNegative();
|
|
if (inv) root = root.negated();
|
|
|
|
if (root.isZero()) throw new Error('Root must be non-zero');
|
|
if (a.isNegative() && !root.abs().mod(2).equals(1)) throw new Error('Root must be odd when a is negative.');
|
|
|
|
// edge cases zero and infinity
|
|
if (a.isZero()) return zero;
|
|
if (!a.isFinite())
|
|
{
|
|
return inv ? zero : a;
|
|
}
|
|
|
|
var x = one; // Initial guess
|
|
var i = 0;
|
|
var iMax = 100;
|
|
do {
|
|
var xPrev = x;
|
|
var delta = a.div(x.pow(root.minus(1))).minus(x).div(root);
|
|
x = x.plus(delta);
|
|
i++;
|
|
}
|
|
while (!x.equals(xPrev) && i < iMax);
|
|
|
|
return inv ? one.div(x) : x;
|
|
}
|
|
}
|
|
|
|
/**
|
|
* Calculate the nth root of a, solve x^root == a
|
|
* http://rosettacode.org/wiki/Nth_root#JavaScript
|
|
* @param {number} a
|
|
* @param {number} root
|
|
* @private
|
|
*/
|
|
function _nthRoot(a, root) {
|
|
var inv = root < 0;
|
|
if (inv) root = -root;
|
|
|
|
if (root === 0) throw new Error('Root must be non-zero');
|
|
if (a < 0 && (Math.abs(root) % 2 != 1)) throw new Error('Root must be odd when a is negative.');
|
|
|
|
// edge cases zero and infinity
|
|
if (a == 0) return 0;
|
|
if (!Number.isFinite(a)) {
|
|
return inv ? 0 : a;
|
|
}
|
|
|
|
var epsilon = 1e-16;
|
|
var x = 1; // Initial guess
|
|
var i = 0;
|
|
var iMax = 100;
|
|
do {
|
|
var delta = (a / Math.pow(x, root - 1) - x) / root;
|
|
x = x + delta;
|
|
i++;
|
|
}
|
|
while (Math.abs(delta) > epsilon && i < iMax);
|
|
|
|
return inv ? 1 / x : x;
|
|
}
|
|
|
|
exports.name = 'nthRoot';
|
|
exports.factory = factory;
|