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22a12567f8
Note for this to work in a broad variety of contexts, has to also allow identical expressions to cancel regardless of whether subtraction is always defined; but this seems safe in general, that x-x is 0 even if x does not generally have an additive inverse (for example, when working in the positive context). Resolves #1260.
33 lines
1003 B
JavaScript
33 lines
1003 B
JavaScript
import assert from 'assert'
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import math from '../../../../src/defaultInstance.js'
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function assertFalse (val) {
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assert(!val)
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}
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describe('symbolicEqual', function () {
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it('relates anything to itself', function () {
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assert(math.symbolicEqual('x', 'x'))
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assert(math.symbolicEqual('foo(x)', 'foo(x)'))
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})
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it('does not relate different variables', function () {
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assertFalse(math.symbolicEqual('x', 'y'))
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assertFalse(math.symbolicEqual('foo(x)+bar(x)', 'foo(x)+bar(y)'))
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})
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it('handles various manipulations', function () {
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assert(math.symbolicEqual('3x', 'x*3'))
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assert(math.symbolicEqual('x*y', 'y*x'))
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assert(math.symbolicEqual('x*y^2', 'y*x*y'))
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assert(math.symbolicEqual('x*(2y - y -y)', '0*z'))
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})
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it('responds to context', function () {
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assertFalse(math.symbolicEqual(
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'x*y', 'y*x', { context: { multiply: { commutative: false } } }))
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assert(math.symbolicEqual(
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'abs(x)', 'x', { context: math.simplify.positiveContext }))
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})
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})
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