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b6f2ff1ba7
This patch will allow the user to use binary literals starting with 0b or 0B, these literals will be evaluated in parsing time resulting an integer Co-authored-by: Robert Fancsik frobert@inf.u-szeged.hu JerryScript-DCO-1.0-Signed-off-by: Adam Szilagyi aszilagy@inf.u-szeged.hu
53 lines
1.5 KiB
JavaScript
53 lines
1.5 KiB
JavaScript
/* Copyright JS Foundation and other contributors, http://js.foundation
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*
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* Licensed under the Apache License, Version 2.0 (the "License");
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* you may not use this file except in compliance with the License.
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* You may obtain a copy of the License at
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*
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* http://www.apache.org/licenses/LICENSE-2.0
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*
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* Unless required by applicable law or agreed to in writing, software
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* distributed under the License is distributed on an "AS IS" BASIS
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* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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* See the License for the specific language governing permissions and
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* limitations under the License.
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*/
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function checkSyntaxError (str) {
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try {
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eval(str);
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assert(false);
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} catch (e) {
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assert(e instanceof SyntaxError);
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}
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}
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// Test with invalid literals
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checkSyntaxError("0c");
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checkSyntaxError("0b");
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checkSyntaxError("0b0123456");
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checkSyntaxError("0b2");
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checkSyntaxError("0C");
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checkSyntaxError("0B");
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checkSyntaxError("0B2");
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checkSyntaxError("000b01010101");
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checkSyntaxError("010b01010101");
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checkSyntaxError("11 0b01010101");
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// Test with valid literals
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assert(0b111 === 7);
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assert(0b111110111 === 503);
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assert(0b111101010101 === 3925);
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assert(0b00000000000001 === 1);
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assert(0b00000000000000 === 0);
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assert(0b1101001 === parseInt ("1101001", 2));
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assert(0B111 === 7);
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assert(0B111110111 === 503);
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assert(0B111101010101 === 3925);
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assert(0B00000000000001 === 1);
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assert(0B00000000000000 === 0);
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assert(0B1101001 === parseInt ("1101001", 2));
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