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41 lines
1.5 KiB
JavaScript
41 lines
1.5 KiB
JavaScript
/**
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* DYNAMIC PROGRAMMING approach of solving Unique Paths problem.
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*
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* @param {number} width - Width of the board.
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* @param {number} height - Height of the board.
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* @return {number} - Number of unique paths.
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*/
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export default function dpUniquePaths(width, height) {
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// Init board.
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const board = Array(height).fill(null).map(() => {
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return Array(width).fill(0);
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});
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// Base case.
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// There is only one way of getting to board[0][any] and
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// there is also only one way of getting to board[any][0].
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// This is because we have a restriction of moving right
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// and down only.
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for (let rowIndex = 0; rowIndex < height; rowIndex += 1) {
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for (let columnIndex = 0; columnIndex < width; columnIndex += 1) {
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if (rowIndex === 0 || columnIndex === 0) {
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board[rowIndex][columnIndex] = 1;
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}
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}
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}
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// Now, since we have this restriction of moving only to the right
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// and down we might say that number of unique paths to the current
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// cell is a sum of numbers of unique paths to the cell above the
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// current one and to the cell to the left of current one.
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for (let rowIndex = 1; rowIndex < height; rowIndex += 1) {
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for (let columnIndex = 1; columnIndex < width; columnIndex += 1) {
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const uniquesFromTop = board[rowIndex - 1][columnIndex];
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const uniquesFromLeft = board[rowIndex][columnIndex - 1];
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board[rowIndex][columnIndex] = uniquesFromTop + uniquesFromLeft;
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}
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}
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return board[height - 1][width - 1];
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}
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