Espruino/tests/test_string_indexof.js
2014-04-08 08:58:20 +01:00

19 lines
244 B
JavaScript

var a = "ABCD";
var r = [
a.indexOf("A"), 0,
a.indexOf("ABCD"), 0,
a.indexOf("BC"), 1,
a.indexOf("C"), 2,
a.indexOf("D"), 3,
a.indexOf("CD"), 2,
a.indexOf("X"), -1,
];
result = 1;
for (i=0;i<r.length;i+=2)
if (r[i]!=r[i+1])
result=0;